Dear OF Team,

Is there a way to do the following test more nicely/shorter: tree[species=1 or species=8 or species=10 or species=11 or species=12 or species=16 or species=19 or species=22 or species=23]

What I'm looking for is something like this (e.g. in R): tree[species %in% c(1,8,10,11,12,16,19,22,23)]

Could this be implemented if doesn't exist yet?

Thanks! Andras

asked 17 May, 11:42

Andras's gravatar image

Andras
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accept rate: 0%


Hi András,
In the latest version of Collect (3.22.x) there is a new function idm:array that you could use in combination with idm:contains function to simplify your expression, that will become:

idm:contains(idm:array(1,8,10,11,12,16,19,22,23), species)

Many thanks,
Open Foris Team

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answered 07 Jun, 10:41

OF%20Collect's gravatar image

OF Collect ♦♦
1.9k5
accept rate: 19%

Hi,

It seems there is a problem with the expression above. If I try to use it to get a subset of a group of items, it doesn't work:

count(parent()/tree[idm:contains(idm:array(1,8,10,11,12,16,19,22,23),species)])

Am I doing something wrong?

(26 Jun, 10:26) Andras Andras's gravatar image

The species code is an alphanumeric value, so it must be wrapped into single or double quotes. Try to use this expression instead: count(parent()/tree[idm:contains(idm:array('1','8','10','11','12','16','19','22','23'),species)])
However, I would split the expression into 2 separate calculated attributes, one attribute that says if a species in of a specific type and the other one that counts the trees of that species, and I would even move the count outside of the 'tree' entity, since it does not depend on the current tree item.

(26 Jun, 14:28) OF Collect ♦♦ OF%20Collect's gravatar image
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question asked: 17 May, 11:42

question was seen: 88 times

last updated: 26 Jun, 14:28